Folded Dipole Calculator





Folded Dipole Calculator | {primary_keyword}


{primary_keyword} | Precise Folded Dipole Calculator

Use this {primary_keyword} to find the exact folded dipole arm length, total conductor length, and expected impedance with real-time visuals for RF design.

Folded Dipole Calculator


Enter target center frequency for the folded dipole.

Typical velocity factor for wire or ladder line ranges 0.8–0.98.

Standard folded dipole uses 2 parallel conductors; more conductors raise impedance.

Recommended Folded Dipole Arm Length: — m
Free-Space Half-Wave Length: — m
Adjusted Half-Wave with Velocity Factor: — m
Total Conductor Length (all arms): — m
Estimated Feed Impedance: — Ω
Formula used: Adjusted half-wave length = (150 / Frequency in MHz) × Velocity Factor. Each arm of the {primary_keyword} equals the adjusted half-wave. Total conductor length equals adjusted half-wave multiplied by the number of conductors. Feed impedance ≈ 73 × (Number of Conductors)2. This {primary_keyword} applies classic half-wave dipole theory to folded geometries.
Table: Frequency sweep impact on {primary_keyword} dimensions
Freq (MHz) Half-Wave Free-Space (m) Adjusted Arm Length (m) Total Conductor Length (m) Feed Impedance (Ω)

Free-Space Half-Wave
Adjusted Arm Length

What is {primary_keyword}?

The {primary_keyword} is a specialized RF design tool that computes folded dipole dimensions for accurate antenna construction. Engineers, amateur radio operators, and RF installers rely on the {primary_keyword} to determine arm length, total conductor length, and impedance tailored to a desired frequency. The {primary_keyword} clarifies how velocity factor and conductor count alter physical length and feed impedance. Many assume all dipoles are identical, yet the {primary_keyword} shows that folded geometries behave differently, demanding precise math. Because the {primary_keyword} integrates velocity factor, users avoid the misconception that vacuum speed applies to every build. The {primary_keyword} also corrects the myth that a folded dipole is simply twice the wire; instead, the {primary_keyword} highlights how conductor count raises impedance while maintaining half-wave resonance.

Anyone who tunes VHF, UHF, or HF antennas should apply the {primary_keyword} before cutting wire. Broadcast engineers use the {primary_keyword} to match transmission lines. Field technicians carry the {primary_keyword} to make rapid adjustments. Hobbyists choose the {primary_keyword} to avoid trial-and-error. In every scenario, the {primary_keyword} reduces wasted material and ensures dependable matching.

{primary_keyword} Formula and Mathematical Explanation

The {primary_keyword} is grounded in half-wave resonance: λ/2 = c / (2f). The {primary_keyword} replaces c with an effective speed that includes velocity factor, so length = (150 / f) × VF in meters. The {primary_keyword} then assigns each conductor arm the adjusted half-wave. By multiplying by the number of conductors, the {primary_keyword} outputs total conductor length. For impedance, the {primary_keyword} applies Z = 73 × N², linking conductor count to impedance. Each step of the {primary_keyword} traces RF physics into tangible build dimensions.

Step-by-step within the {primary_keyword}: (1) compute free-space half-wave; (2) apply velocity factor; (3) set arm length equal to adjusted half-wave; (4) scale total conductor length by conductor count; (5) estimate feed impedance by squaring conductor count and multiplying by 73. Variables in the {primary_keyword} appear below.

Variables used by the {primary_keyword}
Variable Meaning Unit Typical Range
f Operating frequency in the {primary_keyword} MHz 1–500
VF Velocity factor applied by the {primary_keyword} ratio 0.8–0.99
N Number of conductors in the {primary_keyword} count 1–4
λ/2 Free-space half-wave from the {primary_keyword} m 0.6–150
Larm Arm length from the {primary_keyword} m 0.5–140
Zin Impedance predicted by the {primary_keyword} Ω 73–1200+

Practical Examples (Real-World Use Cases)

Example 1: VHF Broadcast at 100 MHz

Using the {primary_keyword}, set f=100 MHz, VF=0.95, N=2. The {primary_keyword} yields a free-space half-wave of 1.5 m, adjusted arm length 1.425 m, total conductor length 2.85 m, and feed impedance about 292 Ω. This {primary_keyword} output guides a precise 300 Ω match with balanced line.

Example 2: HF Dipole at 14.2 MHz

Enter f=14.2 MHz, VF=0.9, N=2 in the {primary_keyword}. The {primary_keyword} returns a free-space half-wave of 10.56 m, adjusted arm length 9.5 m, total conductor length 19 m, and impedance near 292 Ω. Builders use the {primary_keyword} to cut wire and pair with a 4:1 balun for coax feed.

Example 3: High-Impedance Fold with 3 Conductors

With f=50 MHz, VF=0.92, N=3, the {primary_keyword} calculates 3 m free-space half-wave, 2.76 m arm length, total conductor length 8.28 m, and impedance 657 Ω, showcasing how the {primary_keyword} scales impedance for specialized networks.

How to Use This {primary_keyword} Calculator

  1. Enter operating frequency; the {primary_keyword} instantly sets half-wave.
  2. Adjust velocity factor to match your wire or feed; the {primary_keyword} recalculates arm length.
  3. Pick conductor count; the {primary_keyword} updates impedance and total length.
  4. Review the primary arm length result; the {primary_keyword} highlights it.
  5. Check intermediate values; the {primary_keyword} shows free-space and adjusted lengths.
  6. Use the chart; the {primary_keyword} plots how length shifts across nearby frequencies.

Reading results: the {primary_keyword} main value is the per-arm cut length. The table in the {primary_keyword} section shows frequency sweeps. Use the {primary_keyword} impedance to select a balun or line.

Decision-making: if the {primary_keyword} shows impedance near 300 Ω, a 4:1 balun suits 75 Ω coax. If the {primary_keyword} predicts higher impedance, adjust conductor count or choose ladder line. The {primary_keyword} allows quick iteration without wasting wire.

Explore related guidance with {related_keywords} inside this {primary_keyword} workflow.

Key Factors That Affect {primary_keyword} Results

  • Velocity Factor: The {primary_keyword} scales arm length by VF; lower VF shortens the dipole.
  • Operating Frequency: The {primary_keyword} inversely ties length to frequency; small frequency errors change resonance.
  • Conductor Count: The {primary_keyword} squares count for impedance, raising feed resistance.
  • Conductor Diameter and Spacing: Though simplified, the {primary_keyword} assumes typical spacing; changes may slightly shift VF.
  • Environment and Nearby Objects: The {primary_keyword} presumes free space; roofs or masts detune length.
  • Balun and Feedline Choice: The {primary_keyword} impedance guides balun ratios; mismatches increase SWR.
  • Temperature and Weathering: The {primary_keyword} does not adjust for ice or rain; physical changes can detune.
  • Installation Height: The {primary_keyword} assumes half-wave resonance; ground proximity may alter pattern.

For extended reading, see {related_keywords} and {related_keywords} as part of the {primary_keyword} planning.

Frequently Asked Questions (FAQ)

Does the {primary_keyword} work for any band?

The {primary_keyword} covers HF to UHF as long as frequency and VF are known.

How accurate is the impedance from the {primary_keyword}?

The {primary_keyword} provides a theoretical impedance; real-world values vary with spacing and wire diameter.

Can I use the {primary_keyword} for single-wire dipoles?

Yes, set conductor count to 1 and the {primary_keyword} reverts to classic dipole values.

What if my velocity factor is unknown?

The {primary_keyword} suggests 0.95 for typical copper wire; fine-tune with measurements.

Does the {primary_keyword} handle very low frequencies?

The {primary_keyword} can calculate long lengths; ensure your space fits the result.

Can the {primary_keyword} output imperial units?

This {primary_keyword} displays meters; convert externally or adjust code to multiply by 3.281.

Why is my measured SWR different from the {primary_keyword} prediction?

Installation factors and nearby structures change resonance; the {primary_keyword} assumes ideal conditions.

How do I match a 50 Ω coax with the {primary_keyword}?

Use the {primary_keyword} impedance to choose a balun ratio (e.g., 4:1 for ~200–300 Ω).

Find more answers with {related_keywords} and {related_keywords} linked to this {primary_keyword} resource.

Related Tools and Internal Resources

Leverage this {primary_keyword} to streamline every folded dipole project and combine it with {related_keywords} for complete RF success.



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